NCERT Math Class 6th Question – 7 Exercise 3.7 |
Three tankers contain 403 litres, 434 litres and 465 litres of diesel respectively. Find the maximum capacity of a container that can measure the diesel of the three containers exact number of times. Solution: Maximum capacity of the required measure is equal to the HCF of 403, 434 and 465.
Prime factorisations of 403, 434 and 465 are
Common factor = 31.
So, the HCF of 403, 434 and 465 = 31.
Hence, the maximum capacity of the required container = 31 litres. |
NCERT Math Class 6th Question – 1 Exercise 3.7 | Click here |
NCERT Math Class 6th Question – 2 Exercise 3.7 | Click here |
NCERT Math Class 6th Question – 3 Exercise 3.7 | Click here |
NCERT Math Class 6th Question – 4 Exercise 3.7 | Click here |
NCERT Math Class 6th Question – 5 Exercise 3.7 | Click here |
NCERT Math Class 6th Question – 6 Exercise 3.7 | Click here |
NCERT Math Class 6th Question – 8 Exercise 3.7 | Click here |
NCERT Math Class 6th Question – 9 Exercise 3.7 | Click here |
NCERT Math Class 6th Question – 10 Exercise 3.7 | Click here |
NCERT Math Class 6th Question – 11 Exercise 3.7 | Click here |
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