NCERT Solutions Class 9th Science Chapter – 9 Gravitation Question & Answer

NCERT Solutions Class 9th Science Chapter – 9 Gravitation

TextbookNCERT
Class 9th
Subject Science 
Chapter9th
Chapter NameGravitation 
CategoryClass 9th Science
Medium English
SourceLast Doubt
NCERT Solutions Class 9th Science Chapter – 9 Gravitation Question & Answer What is called gravitation? What is gravitation and its formula? Is gravitation a ?, What is the SI unit of gravitation?, Why is it called gravitation?, What is called gravitation?, Who discovered gravitation?, What is gravitation and its types?, What is the principle of gravity?, What is the value of G?, What is the unit of force?, What is 9.8 newton equal to?, What is 1 newton? , How much is 1 newton?, What is Newtons first law?, Is joule a SI unit?, What is newton formula?, What are the 3 types of newton law?, What is the law of inertia?, What is Newtons in kg? What is 9.8 N in kg? What is the unit of mass? What is kgf in physics?

NCERT Solutions Class 9th Science Chapter – 9 Gravitation

Chapter – 9

Gravitation

Question & Answer

Page: 102

Question 1. State the universal law of gravitation.

Answer- The universal law of gravitation states that every object in the universe attracts every other object with a force called the gravitational force. The force acting between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
Question 2. Write the formula to find the magnitude of the gravitational force between the earth and an object on the surface of the earth.

Answer- Consider F as the force of attraction between an object on the surface of earth and the earth Also, consider ‘m’ as the mass of the object on the surface of earth and ‘M’ as the mass of earth
The distance between the earth’s centre and object = Radius of the earth = R

• Therefore, the formula for the magnitude of the gravitational force between the earth and an object on the surface is given as
F = G Mm/R2

Page: 104

Question 1. What do you mean by free fall?

Answer- Earth’s gravity attracts each object to its center. When an object is dropped from a certain height, under the influence of gravitational force it begins to fall to the surface of Earth. Such an object movement is called free fall.
Question 2. What do you mean by acceleration due to gravity?

Answer- When an object falls freely towards the surface of earth from a certain height, then its velocity changes and this change in velocity produces acceleration in the object which is known as acceleration due to gravity denoted by g. The value of acceleration due to gravity is. g = 9. 8m/s2.

Page: 106

Question 1. What are the differences between the mass of an object and its weight?

Answer –
MassWeight
1.The measure of the amount of matter in a body.1.The measure of the amount of force acting on a mass due to acceleration due to gravity.
2. Mass = volume × density2.Weight = mass × acceleration due to gravity
3.The SI unit of mass is kilogram (kg).3.The SI unit of weight is newton (N).
4. It is a scalar quantity.4. It is a vector quantity.
5. Mass is the measure of the amount of matter in a body. 6. Weight is the measure of the amount of force acting on a mass due to the acceleration due to gravity.
Question 2. Why is the weight of an object on the moon 1/6th its weight on the earth?

Answer- The mass of the moon is 1/100 times and its radius 1/4 times that of earth. As a result, the gravitational attraction on the moon is about one-sixth when compared to earth. The moon’s gravitation force is determined by the mass and the size of the moon. Hence, the weight of an object on the moon is 1/6th its weight on the earth. The moon is far less massive than the Earth and has a different radius(R) as well.

Page: 109

Question 1. Why is it difficult to hold a school bag having a strap made of a thin and strong string?

Answer- It is tough to carry a school bag having a skinny strap because of the pressure that is being applied on the shoulders. The pressure is reciprocally proportional to the expanse on which the force acts. So, the smaller the surface area, the larger is going to be the pressure on the surface. In the case of a skinny strap, the contact expanse is quite small. Hence, the pressure exerted on the shoulder is extremely huge.
Question 2. What do you mean by buoyancy?

Answer- The upward force possessed by a liquid on an object that’s immersed in it is referred to as buoyancy.
Question 3. Why does an object float or sink when placed on the surface of water?

Answer- An object floats or sinks when placed on the surface of water because of two reasons.

(i) If its density is greater than that of water, an object sinks in water.
(ii) If its density is less than that of water, an object floats in water.

Page: 110

Question 1. You find your mass to be 42 kg on a weighing machine. Is your mass more or less than 42 kg?

Answer- A weighing machine measures the body weight and is calibrated to indicate the mass. If we stand on a weighing machine, the weight acts downwards while the upthrust due to air acts upwards. So our apparent weight becomes less than the true weight. This apparent weight is measured by the weighing machine and therefore the mass indicated is less than the actual mass. So our actual mass will be more than 42 kg.
Question 2. You have a bag of cotton and an iron bar, each indicating a mass of 100 kg when measured on a weighing machine. In reality, one is heavier than other. Can you say which one is heavier and why?

Answer- The correct answer is the cotton bag is heavier than an iron bar. The bag of cotton is heavier than the bar of iron. The cotton bag experiences a larger air thrust than the iron bar. Therefore, the weighing machine indicates less weight than its actual weight for the cotton bag. The reason is
True weight = (apparent weight + up thrust)

The cotton bag’s density is less than that of the iron bar, so the volume of the cotton bag is more compared to the iron bar. So the cotton bag experience more upthrust due to the presence of air.
Therefore, in the presence of air, the cotton bag’s true weight is more compared to the true weight of the iron bar.
 

Page: 111

Question 1. How does the force of gravitation between two objects change when the distance between them is reduced to half?

Answer- Consider the Universal law of gravitation,
According to that law, the force of attraction between two bodies is
Where,
m1 and m2 are the masses of the two bodies.
G is the gravitational constant.
r is the distance between the two bodies.
Given that the distance is reduced to half then,
r = 1/2 r
Therefore,
F = 4F
Therefore once the space between the objects is reduced to half, then the force of gravitation will increase by fourfold the first force.
Question 2. Gravitational force acts on all objects in proportion to their masses. Why then does a heavy object not fall faster than a light object?

Answer- All objects fall from the top with a constant acceleration called acceleration due to gravity (g). This is constant on earth and therefore the value of ‘g’ doesn’t depend on the mass of an object. Hence, heavier objects don’t fall quicker than light-weight objects provided there’s no air resistance.
Question 3. What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 1024 kg and radius of the earth is 6.4 × 106m.)

Answer- Given that,Mass of the body, m = 1 kg
Mass of the Earth, M = 6×1024 kg
Radius of the Earth, R= 6.4×106 m
From the universal law of gravitation, the magnitude of the gravitational force (F) between the earth and the body is given by,F= GM×m/R2where G = 6.67×10−11 Nm2/kg2 is the universal gravitational constant.
Hence, magnitude of the gravitational force (F) between the earth and the body is given by,
F=GM×m/R2
=6.67×10−11×6×1024×1/(6.4×106)2 
= 9.77 N
= 9.8 N (approx).
Question 4. The earth and the moon are attracted to each other by gravitational force. Does the earth attract the moon with a force that is greater or smaller or the same as the force with which the moon attracts the earth? Why?

Answer- Let m and M be the mass of moon and earth respectively which are separated by a distance rForce of attraction that earth exert on moon, Fe ​= GMm/r2
Force of attraction that moon exert on earth, Fm ​= GmM/r2Thus earth attracts the moon with same force by which moon attracts the  earth.

Also the gravitational force is an internal force of attraction between the two bodies, thus they have to be equal.
Question 5. If the moon attracts the earth, why does the earth not move towards the moon?

Answer- According to the universal law of gravitation and Newton’s third law, we all know that the force of attraction between two objects is the same, however in the opposite directions. So the earth attracts the moon with a force same as the moon attracts the earth but in opposite directions. Since earth is larger in mass compared to that of the moon, it accelerates at a rate lesser than the acceleration rate of the moon towards the Earth. Therefore, for this reason the earth does not move towards the moon.
Question 6. What happens to the force between two objects, if

(i) The mass of one object is doubled?
Answer- (i)According to universal law of gravitation, the force between 2 objects (m1 and m2) is proportional to their plenty and reciprocally proportional to the sq. of the distance(R) between them.If the mass is doubled for one object.
F = 2F, so the force is also doubled.

(ii) The distance between the objects is doubled and tripled?
Answer- If the distance between the objects is doubled and tripled
If it’s doubled
Hence,
F = (Gm1m2)/(2R)2
F = 1/4 (Gm1m2)/R2
F = F/4
Force thus becomes one-fourth of its initial force.Now, if it’s tripled
Hence,
F = (Gm1m2)/(3R)2
F = 1/9 (Gm1m2)/R2
F = F/9
Force thus becomes o
ne-ninth of its initial force.

(iii) The masses of both objects are doubled?
Answer- If masses of both the objects are doubled, then
F = 4F, Force will therefore be four times greater than its actual value.
Question 7. What is the importance of universal law of gravitation?

Answer- The universal law of gravitation explains many phenomena that were believed to be unconnected:

(i) The motion of the moon round the earth
(ii) The responsibility of gravity on the weight of the body which keeps us on the ground
(iii) The tides because of the moon and therefore the Sun
(iv) The motion of planets round the Sun
Question 8. What is the acceleration of free fall?

Answer- Acceleration due to gravity is the acceleration gained by an object due to gravitational force. On Earth, all bodies experience a downward force of gravity which Earth’s mass exerts on them. The Earth’s gravity is measured by the acceleration of the freely falling objects. At Earth’s surface, the acceleration of gravity is 9.8 ms-2 and it is denoted by ‘g’. Thus, for every second an object is in free fall, its speed increases by about 9.8 metres per second.
Question 9. What do we call the gravitational force between the earth and an object?

Answer- The gravitation force between the earth and an object is called weight. Weight is equal to the product of acceleration due to the gravity and mass of the object.
Question 10. Amit buys few grams of gold at the poles as per the instruction of one of his friends. He hands over the same when he meets him at the equator. Will the friend agree with the weight of gold bought? If not, why? [Hint: The value of g is greater at the poles than at the equator.]

Answer- The weight of a body on the earth’s surface;
W = mg (where m = mass of the body and g = acceleration due to gravity)
The value of g is larger at poles when compared to the equator. So gold can weigh less at the equator as compared to the poles.
Therefore, Amit’s friend won’t believe the load of the gold bought.
Question 11. Why will a sheet of paper fall slower than one that is crumpled into a ball?

Answer- A sheet of paper has a larger surface area when compared to a crumpled paper ball. A sheet of paper will face a lot of air resistance. Thus, a sheet of paper falls slower than the crumpled ball.
Question 12. Gravitational force on the surface of the moon is only 1/6 as strong as gravitational force on the earth. What is the weight in newton’s of a 10 kg object on the moon and on the earth?

Answer- Given data: Acceleration due to earth’s gravity = ge or g = 9.8 m/s2
Object’s mass, m = 10 kg
Acceleration due to moon gravity = gm
Weight on the earth = We
Weight on the moon = Wm
Weight = mass x gravity
gm = (1/6) ge (given)
So Wm = m gm = m x (1/6) ge
Wm = 10 x (1/6) x 9.8 = 16.34 N
We = m x ge = 10 x 9.8
We = 98N
Question 13. A ball is thrown vertically upwards with a velocity of 49 m/s.
Calculate

(i) The maximum height to which it rises,
(ii) The total time it takes to return to the surface of the earth.

Answer- The initial velocity of the ball u = 49 m/s
The final velocity of the ball v = 0
Let the acceleration due to gravity be g = 9.8 m/s2
Let the time taken to go up be t.
Step 2: Calculate the Height
According to Newton’s first equation of motion
v = u – gt
Acceleration is given as negative since the ball moves upwards against gravity.
0 = 49-9.8×t
49 = 9.8×t
t = 49/9.8
t = 5 s
Therefore the total time to return to the surface of the earth = 2t = 2 × 5 = 10 s
Hence, the total time the ball takes to return to the surface of the earth is 10 s.
Question 14. A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground.

Answer-
Given data: Initial velocity
u = 0
Tower height = total distance = 19.6m
g = 9.8 m/s2
Consider third equation of motion
v2 = u2 + 2gs
v2 = 0 + 2 × 9.8 × 19.6
v2 = 384.16
v = √(384.16)
v = 19.6m/s
Question 15. A stone is thrown vertically upward with an initial velocity of 40 m/s. Taking g = 10 m/s2, find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?

Answer-
Given data: Initial velocity u = 40m/s
g = 10 m/s2
Max height final velocity = 0
Consider third equation of motion
v2 = u2 – 2gs [negative as the object goes up]
0 = (40)2– 2 x 10 x s
s = (40 x 40) / 20
Maximum height s = 80m
Total Distance = s + s = 80 + 80
Total Distance = 160m
Total displacement = 0 (The first point is the same as the last point)
Question 16. Calculate the force of gravitation between the earth and the Sun, given that the mass of the earth = 6 × 1024 kg and of the Sun = 2 × 1030 kg. The average distance between the two is 1.5 × 1011 m.

Answer-
Given data:
Mass of the sun ms = 2 × 1030 kg
Mass of the earth me = 6 × 1024 kg
Gravitation constant G = 6.67 x 10-11 N m2/ kg2
Average distance r = 1.5 × 1011 m
Consider Universal law of Gravitation
Question 17. A stone is allowed to fall from the top of a tower 100 m high and at the same time another stone is projected vertically upwards from the ground with a velocity of 25 m/s. Calculate when and where the two stones will meet.

Answer- For upper stone  :            u′= 0         
x = 0 + 1/2gt2
x = 1/2 ​× 10 × t2           
x = 5t2          …………(1)
 
For lower stone :            
u = 25  m/s  
100 − x = ut − 1/2gt2
100 − x = (25)t − 1/2 ​× 10 × t2          
100 − x = 25t − 5t2            …………(2)
 
Adding (1) and (2),  we get          
25t = 100              
t = 4 s        
 
From (1),            
x = 5 × 42               
x = 80 m 
Hence the stone meet at a height of   20 m above the ground after 4 seconds.
Question 18. A ball thrown up vertically returns to the thrower after 6 s. Find

Answer- The ball returns to the ground after 6 seconds.Thus the time taken by the ball to reach to the maximum height (h) is 3 seconds i.e t = 3 s
Let the velocity with which it is thrown up be  u
 
(a) The velocity with which it was thrown up,
Answer- For upward motion,               
v = u + at
 0 = u + (−10) × 3                 
u = 30  m/s     
 
(b) The maximum height it reaches, and
Answer- The maximum height reached by the ball
h = ut + 1/2​ at2
h = 30 × 3 + 1/2​(−10) × 32              
h = 45 m  
 
(c) Its position after 4s.
Answer- After 3 second, it starts to fall down. 
Let the distance by which it fall in 1 s   be   d
d = 0 + 1/2​at2                       where   t′ = 1 s
d = 1/2 ​× 10 × (1)2    = 5 m  

∴ Its height above the ground, h′= 45 − 5 = 40 m 
Hence after 4 s, the ball is at a height of 40 m above the ground.   
Question 19. In what direction does the buoyant force on an object immersed in a liquid act?

Answer- The buoyant force on an object that is immersed in a liquid will be in a vertically upward direction.
Question 20. Why a block of plastic when released under water come up to the surface of water?

Answer- The density of plastic is lesser than that of water. Therefore, the force of buoyancy on plastic block will be greater than the weight of plastic block. Hence, the acceleration of plastic block is going to be in the upward direction. So, the plastic block comes up to the surface of water.
Question 21. The volume of 50 g of a substance is 20 cm3. If the density of water is 1 g cm–3, will the substance float or sink?

Answer- To find the Density of the substance the formula is
Density = (Mass/Volume)
Density = (50/20) = 2.5g/cm3
Density of water = 1g/cm3
Density of the substance is greater than density of water. So the substance will sink.
Question 22. The volume of a 500 g sealed packet is 350 cm3. Will the packet float or sink in water if the density of water is 1 g cm–3? What will be the mass of the water displaced by this packet?

Answer-
Density of sealed packet = 500/350 = 1.42 g/cm3
Density of sealed packet is greater than density of water
Therefore the packet will sink.
Considering Archimedes Principle,
Displaced water volume = Force exerted on the sealed packet.
Volume of water displaced = 350cm3
Therefore displaced water mass = ρ x V
= 1 × 350
Mass of displaced water = 350g.

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