NCERT Solutions Class 9th Maths Chapter – 10 Heron’s Formula
Textbook | NCERT |
Class | 9th |
Subject | Mathematics |
Chapter | 10th |
Chapter Name | Heron’s Formula |
Category | Class 9th Math Solutions |
Medium | English |
Source | Last Doubt |
NCERT Solutions Class 9th Maths Chapter – 10 Heron’s Formula
Chapter – 10
Heron’s Formula
Examples
Example 1 : Find the area of a triangle, two sides of which are 8 cm and 11 cm and the perimeter is 32 cm (see Fig. 10.3). Solution – Here we have perimeter of the triangle = 32 cm, a = 8 cm and b = 11 cm. Third side c = 32 cm – (8 + 11) cm = 13 cm Therefore, area of the triangle = √s(-a) (S-c) (s-c) |
Example 2 : A triangular park ABC has sides 120m, 80m and 50m (see Fig. 10.4). A gardener Dhania has to put a fence all around it and also plant grass inside. How much area does she need to plant? Find the cost of fencing it with barbed wire at the rate of `20 per metre leaving a space 3m wide for a gate on one side. Solution – For finding area of the park, we have |
Example 3 : The sides of a triangular plot are in the ratio of 3 : 5 : 7 and its perimeter is 300 m. Find its area. Solution – Suppose that the sides, in metres, are 3x, 5x and 7x (see Fig. 10.5). |
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