NCERT Solutions Class 8th Maths Chapter – 16 Playing with Numbers Exercise 16.1

Find the values of the letters in each of the following and give reasons for the steps involved.

Ncert Solution Class 8th (Chapter – 16) Exercise – 16.1 Question . 1

1.

Solution: Say, A = 7 and we get,
7+5 = 12
In which one’s place is 2.
Therefore, A = 7
And putting 2 and carry over 1, we get
B = 6
Hence A = 7 and B = 6

Ncert Solution Class 8th (Chapter – 16) Exercise – 16.1 Question . 1

2.

Solution: If A = 5 and we get,
8+5 = 13 in which ones place is 3.
Therefore, A = 5 and carry over 1 then
B = 4 and C = 1
Hence, A = 5, B = 4 and C = 1

Ncert Solution Class 8th (Chapter – 16) Exercise – 16.1 Question . 3

3.

Solution: On putting A = 1, 2, 3, 4, 5, 6, 7 and so on and we get,
AxA = 6×6 = 36 in which ones place is 6.
Therefore, A = 6

Ncert Solution Class 8th (Chapter – 16) Exercise – 16.1 Question . 4

4.

Solution: Here, we observe that B = 5 so that 7+5 =12
Putting 2 at ones place and carry over 1 and A = 2, we get
2+3+1 =6
Hence A = 2 and B = 5

Ncert Solution Class 8th (Chapter – 16) Exercise – 16.1 Question . 5

5.

Solution: Here on putting B = 0, we get 0x3 = 0.
And A = 5, then 5×3 =15
A = 5 and C=1
Hence A = 5, B = 0 and C = 1

Ncert Solution Class 8th (Chapter – 16) Exercise – 16.1 Question . 6

6.

Solution: On putting B = 0, we get 0x5 = 0 and A = 5, then 5×5 =25
A = 5, C = 2
Hence A = 5, B = 0 and C =2

Ncert Solution Class 8th (Chapter – 16) Exercise – 16.1 Question . 7

7.

Solution: Here product of B and 6 must be same as ones place digit as B.
6×1 = 6, 6×2 = 12, 6×3 = 18, 6×4 =24
On putting B = 4, we get the ones digit 4 and remaining two B’s value should be44.
Therefore, for 6×7 = 42+2 =44
Hence A = 7 and B = 4

Ncert Solution Class 8th (Chapter – 16) Exercise – 16.1 Question . 8

8.

Solution: On putting B = 9, we get 9+1 = 10
Putting 0 at ones place and carry over 1, we get for A = 7
7+1+1 =9
Hence, A = 7 and B = 9

Ncert Solution Class 8th (Chapter – 16) Exercise – 16.1 Question . 9

9.

Solution: On putting B = 7, we get 7+1 =8
Now A = 4, then 4+7 =11
Putting 1 at tens place and carry over 1, we get
2+4+1 =7
Hence, A = 4 and B = 7

Ncert Solution Class 8th (Chapter – 16) Exercise – 16.1 Question . 10

10.

Solution: Putting A = 8 and B = 1, we get
8+1 =9
Now, again we add2 + 8 =10
Tens place digit is ‘0’ and carry over 1. Now 1+6+1 = 8 =A
Hence A = 8 and B =1