NCERT Solutions Class 7th Math Chapter 4 Simple Equations Exercise 4.2

NCERT Solutions Class 7th Math Chapter 4 Simple Equations

TextbookNCERT
Class 7th
Subject Mathematics
Chapter4th
Chapter NameSimple Equations
CategoryClass 7th Mathematics
Medium English
SourceLast Doubt

NCERT Solutions Class 7th Math Chapter 4 Simple Equations Exercise 4.2 What are the 3 types of equations, How do you solve simple equations, How do you solve a simple equation problem, How to solve a formula, What are the 4 basic rule in solving equation, How do you solve a 3×3 system of equations.

NCERT Solutions Class 7th Maths Chapter 4 Data Handling

Chapter – 4

Data Handling

Exercise 4.2

1. Give first the step you will use to separate the variable and then solve the equation:

(a) – 1 = 0

Solution: We have to add 1 to both the side of given equation,
Then we get,
= x – 1 + 1 = 0 + 1
= x = 1

(b) + 1 = 0

Solution: We have to subtract 1 to both the side of given equation,
Then we get,
= x + 1 – 1 = 0 – 1
= x = – 1

(c) – 1 = 5

Solution: We have to add 1 to both the side of given equation, Then we get,
= x – 1 + 1 = 5 + 1
= x = 6

(d) + 6 = 2

Solution: We have to subtract 6 to both the side of given equation,Then we get,
= x + 6 – 6 = 2 – 6
= x = – 4

(e) – 4 = – 7

Solution: We have to add 4 to both the side of given equation,Then we get,
= y – 4 + 4 = – 7 + 4
= y = – 3

(f) – 4 = 4

Solution: We have to add 4 to both the side of given equation,Then we get,
= y – 4 + 4 = 4 + 4
= y = 8

(g) + 4 = 4

Solution: We have to subtract 4 to both the side of given equation,Then we get,
= y + 4 – 4 = 4 – 4
= y = 0

(h) + 4 = – 4

Solution: We have to subtract 4 to both the side of given equation,Then we get,
= y + 4 – 4 = – 4 – 4
= y = – 8

2. Give first the step you will use to separate the variable and then solve the equation:

(a) 3l = 42

Solution: Now we have to divide both sides of the equation by 3,Then we get,
= 3l/3 = 42/3
= l = 14

(b) b/2 = 6

Solution: Now we have to multiply both sides of the equation by 2,Then we get,
= b/2 × 2= 6 × 2
= b = 12

(c) p/7 = 4

Solution: Now we have to multiply both sides of the equation by 7,Then we get,
= p/7 × 7= 4 × 7
= p = 28

(d) 4x = 25

Solution: Now we have to divide both sides of the equation by 4,Then we get,
= 4x/4 = 25/4
= x = 25/4

(e) 8y = 36

Solution: Now we have to divide both sides of the equation by 8,Then we get,
= 8y/8 = 36/8
= x = 9/2

(f) (z/3) = (5/4)

Solution: Now we have to multiply both sides of the equation by 3,Then we get,
= (z/3) × 3 = (5/4) × 3
= x = 15/4

(g) (a/5) = (7/15)

Solution: Now we have to multiply both sides of the equation by 5,Then we get,
= (a/5) × 5 = (7/15) × 5
= a = 7/3

(h) 20t = – 10

Solution: Now we have to divide both sides of the equation by 20,Then we get,
= 20t/20 = -10/20
= x = – ½

3. Give the steps you will use to separate the variable and then solve the equation:

(a) 3n – 2 = 46

Solution: First we have to add 2 to the both sides of the equation,Then, we get,
= 3n – 2 + 2 = 46 + 2
= 3n = 48
Now,
We have to divide both sides of the equation by 3,Then, we get,
= 3n/3 = 48/3
= n = 16

(b) 5m + 7 = 17

Solution: First we have to subtract 7 to the both sides of the equation ,Then, we get,
= 5m + 7 – 7 = 17 – 7
= 5m = 10
Now,
We have to divide both sides of the equation by 5,Then, we get,
= 5m/5 = 10/5
= m = 2

(c) 20p/3 = 40

Solution: First we have to multiply both sides of the equation by 3,Then, we get,
= (20p/3) × 3 = 40 × 3
= 20p = 120
Now,
We have to divide both sides of the equation by 20,Then, we get,
= 20p/20 = 120/20
= p = 6

(d) 3p/10 = 6

Solution: First we have to multiply both sides of the equation by 10,Then, we get,
= (3p/10) × 10 = 6 × 10
= 3p = 60
Now,
We have to divide both sides of the equation by 3,Then, we get,
= 3p/3 = 60/3
= p = 20

4. Solve the following equations:

(a) 10p = 100

Solution: Now,
We have to divide both sides of the equation by 10,Then, we get,
= 10p/10 = 100/10
= p = 10

(b) 10p + 10 = 100

Solution: First we have to subtract 10 to the both sides of the equation,Then, we get,
= 10p + 10 – 10 = 100 – 10
= 10p = 90
Now,
We have to divide both sides of the equation by 10,Then, we get,
= 10p/10 = 90/10
= p = 9

(c) p/4 = 5

Solution:
Now,
We have to multiply both sides of the equation by 4,Then, we get,
= p/4 × 4 = 5 × 4
= p = 20

(d) – p/3 = 5

Solution:
Now,
We have to multiply both sides of the equation by – 3,Then, we get,
= – p/3 × (- 3) = 5 × (- 3)
= p = – 15

(e) 3p/4 = 6

Solution: First we have to multiply both sides of the equation by 4,Then, we get,
= (3p/4) × (4) = 6 × 4
= 3p = 24
Now,
We have to divide both sides of the equation by 3,Then, we get,
= 3p/3 = 24/3
= p = 8

(f) 3s = – 9

Solution: Now,
We have to divide both sides of the equation by 3,Then, we get,
= 3s/3 = -9/3
= s = -3

(g) 3s + 12 = 0

Solution: First we have to subtract 12 to the both sides of the equation,Then, we get,
= 3s + 12 – 12 = 0 – 12
= 3s = -12
Now,
We have to divide both sides of the equation by 3,Then, we get,
= 3s/3 = -12/3
= s = – 4

(h) 3s = 0

Solution: Now,
We have to divide both sides of the equation by 3,Then, we get,
= 3s/3 = 0/3
= s = 0

(i) 2q = 6

Solution: Now,
We have to divide both sides of the equation by 2,Then, we get,
= 2q/2 = 6/2
= q = 3

(j) 2q – 6 = 0

Solution: First we have to add 6 to the both sides of the equation,Then, we get,
= 2q – 6 + 6 = 0 + 6
= 2q = 6
Now,
We have to divide both sides of the equation by 2,Then, we get,
= 2q/2 = 6/2
= q = 3

(k) 2q + 6 = 0

Solution: First we have to subtract 6 to the both sides of the equation,Then, we get,
= 2q + 6 – 6 = 0 – 6
= 2q = – 6
Now,
We have to divide both sides of the equation by 2,Then, we get,
= 2q/2 = – 6/2
= q = – 3

(l) 2q + 6 = 12

Solution: First we have to subtract 6 to the both sides of the equation,Then, we get,
= 2q + 6 – 6 = 12 – 6
= 2q = 6
Now,
We have to divide both sides of the equation by 2,Then, we get,
= 2q/2 = 6/2
= q = 3

NCERT Solution Class 7th Maths All Chapter

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