NCERT Solutions Class 7 Math Chapter 10 Algebraic Expressions Exercise 10.1
Textbook | NCERT |
Class | 7th |
Subject | Math |
Chapter | 10th |
Chapter Name | Algebraic Expressions |
Category | Class 7th Math Solutions |
Medium | English |
Source | Last Doubt |
NCERT Solutions Class 7 Math Chapter 10 Algebraic Expressions Exercise 10.1
Chapter – 10
Algebraic Expressions
Exercise 10.1
1. Get the algebraic expressions in the following cases using variables, constants and arithmetic operations. (i) Subtraction of z from y. Solution: = Y – z (ii) One-half of the sum of numbers x and y. Solution: = ½ (x + y) = (x + y)/2 (iii) The number z multiplied by itself. Solution: = z × z = z2 (iv) One-fourth of the product of numbers p and q. Solution: = ¼ (p × q) = pq/4 (v) Numbers x and y both squared and added. Solution: = x2 + y2 (vi) Number 5 added to three times the product of numbers m and n. Solution: = 3mn + 5 (vii) Product of numbers y and z subtracted from 10. Solution: = 10 – (y × z) = 10 – yz (viii) Sum of numbers a and b subtracted from their product. Solution: = (a × b) – (a + b) = ab – (a + b) |
2. (i) Identify the terms and their factors in the following expressions Show the terms and factors by tree diagrams. (a) x – 3 Solution: (b) 1 + x + x2 Solution: (c) y – y3 Solution: (d) 5xy2 + 7x2y Solution: (e) – ab + 2b2 – 3a2 Solution: (ii) Identify terms and factors in the expressions given below: (a) – 4x + 5 (b) – 4x + 5y (c) 5y + 3y2 (d) xy + 2x2y2 ?♂️Solution: Expressions is defined as, numbers, symbols and operators (such as +. – , × and ÷) grouped together that show the value of something.
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4. (a) Identify terms which contain x and give the coefficient of x. (i) y2x + y (ii) 13y2 – 8yx (iii) x + y + 2 Solution:
(b) Identify terms which contain y2 and give the coefficient of y2. (i) 8 – xy2 (ii) 5y2 + 7x (iii) 2x2y – 15xy2 + 7y2 Solution:
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5. Classify into monomials, binomials and trinomials. (i) 4y – 7z Solution: Binomial. (ii) y2 Solution: Monomial. (iii) x + y – xy Solution: Trinomial. (iv) 100 Solution: Monomial. (v) ab – a – b Solution: Trinomial. (vi) 5 – 3t Solution: Binomial. (vii) 4p2q – 4pq2 Solution: Binomial. (viii) 7mn Solution: Monomial. (ix) z2 – 3z + 8 Solution: Trinomial. (x) a2 + b2 Solution: :Binomial. (xi) z2 + z Solution: Binomial. (xii) 1 + x + x2 Solution: Trinomial. |
6. State whether a given pair of terms is of like or unlike terms. (i) 1, 100 Solution: Like term. (ii) –7x, (5/2)x Solution: Like term. (iii) – 29x, – 29y Solution: Unlike terms. (iv) 14xy, 42yx Solution: Like term. (v) 4m2p, 4mp2 Solution: Unlike terms. (vi) 12xz, 12x2z2 Solution: Unlike terms. |
7. Identify like terms in the following: (a) – xy2, – 4yx2, 8x2, 2xy2, 7y, – 11x2, – 100x, – 11yx, 20x2y, – 6x2, y, 2xy, 3x Solution: When term have the same algebraic factors, they are like terms.They are, (b) 10pq, 7p, 8q, – p2q2, – 7qp, – 100q, – 23, 12q2p2, – 5p2, 41, 2405p, 78qp, 13p2q, qp2, 701p2 Solution: When term have the same algebraic factors, they are like terms.They are, |