NCERT Solutions Class 6th Maths Chapter – 8 Decimals All Examples

Example 1. Which is greater?

(a) 1 or 0.99
(b) 1.09 or 1.093

Solution –

(a) 1 = 1 + 0/10 + 0/100;
0 99 = 0 + 9/10 + 9/100
The whole part of 1 is greater than that of 0.99.
Therefore, 1 > 0.99

(b) 1.09 = 1 + 0/10 + 9/100 + 0/1000;
1.093 = 1 + 0/10 + 9/100 + 3/1000
In this case, the two numbers have same parts upto hundredth.
But the thousandths part of 1.093 is greater than that of 1.09.
Therefore, 1.093 > 1.09.

Example 2. Lata spent ₹ 9.50 for buying a pen and ₹ 2.50 for one pencil. How much money did she spend?

Solution –

Money spent for pen = ₹ 9.50
Money spent for pencil = ₹ 2.50
Total money spent = ₹ 9.50 + ₹ 2.50
Total money spent = ₹ 12.00.

Example 3. Samson travelled 5 km 52 m by bus, 2 km 265 m by car and the rest 1km 30 m he walked. How much distance did he travel in all?

Solution –

Distance travelled by bus = 5 km 52 m = 5.052 km
Distance travelled by car = 2 km 265 m = 2.265 km
Distance travelled on foot = 1 km 30 m = 1.030 km

Therefore, total distance travelled is
5.052 km + 2.265 km + 1.030 km = 8.347 km

Therefore, total distance travelled = 8.347 km.

Example 4. Rahul bought 4 kg 90 g of apples, 2 kg 60 g of grapes and
5 kg 300 g of mangoes. Find the total weight of all the fruits he bought.

Solution –

Weight of apples = 4 kg 90 g = 4.090 kg
Weight of grapes = 2 kg 60 g = 2.060 kg
Weight of mangoes = 5 kg 300 g = 5.300 kg

Therefore, the total weight of the fruits bought is
4.090 kg + 2.060 kg + 5.300 kg = 11.450 kg

Total weight of the fruits bought = 11.450 kg.

Example 5. Abhishek had ₹ 7.45. He bought toffees for ₹ 5.30. Find the balance amount left with Abhishek.

Solution –

Total amount of money = ₹ 7.45
Amount spent on toffees = ₹ 5.30
Balance amount of money = ₹ 7.45 – ₹ 5.30 = ₹ 2.15.

Example 6. Urmila’s school is at a distance of 5 km 350 m from her house. She travels 1 km 70 m on foot and the rest by bus. How much distance does she travel by bus?

Solution –

Total distance of school from the house = 5.350 km
Distance travelled on foot = 1.070 km
Therefore, distance travelled by bus = 5.350 km – 1.070 km = 4.280 km
Thus, distance travelled by bus = 4.280 km or 4 km 280 m.

Example 7. Kanchan bought a watermelon weighing 5 kg 200 g. Out of this she gave 2 kg 750 g to her neighbour. What is the weight of the watermelon left with Kanchan?

Solution –

Total weight of the watermelon = 5.200 kg
Watermelon given to the neighbour = 2.750 kg
Therefore, weight of the remaining watermelon = 5.200 kg – 2.750 kg = 2.450 kg.