NCERT Solutions Class 6th Maths Chapter – 1 Knowing Our Numbers Exercise – 1.3

NCERT Solutions Class 6th Maths Chapter – 1 Knowing Our Numbers

TextbookNCERT
Class 6th
Subject Mathematics
Chapter1st
Chapter NameKnowing Our Numbers
CategoryClass 6th Mathematics 
Medium English
SourceLast Doubt

NCERT Solutions Class 6th Maths Chapter – 1 Knowing Our Numbers help the students who aspire to obtain a good academic score in exams. Experts at Last Doubt designed these solutions to boost the confidence of students by assisting them in understanding the concepts covered in this chapter. NCERT Solutions for Class 6th contains the methods to solve problems present in the book quickly and easily.

NCERT Solutions Class 6th Maths Chapter – 1 Knowing Our Numbers

Chapter – 1

Knowing Our Numbers

Exercise – 1.3

Question 1. Estimate each of the following using general rule:
(a) 730 + 998
(b) 796 – 314
(c) 12,904 + 2,888
(d) 28,292 – 21,496
Make ten more such examples of addition, subtraction and estimation of their outcome.

Solution:
(a) 730 + 998
Rounding off 730 nearest to hundreds = 700
Rounding off 998 nearest to hundreds = 1,000
∴ 730 + 998 = 700 + 1000 = 1700

(b) 796 – 314
Rounding off 796 nearest to hundreds = 800
Rounding off 314 nearest to hundreds = 300
∴ 796 – 314 = 800 – 300 = 500

(c) 12,904 + 2,888
Rounding off 12,904 nearest to thousands = 13000
Rounding off 2888 nearest to thousands = 3000
∴ 12,904 + 2,888 = 13000 + 3000 = 16000

(d) 28,292 – 21,496
Rounding off 28,292 nearest to thousands = 28,000
Rounding off 21,496 nearest to thousands = 21,000
∴ 28,292 – 21,496 = 28,000 – 21,000 = 7,000

Example 1:
Solution:
1210 + 2365 = 1200 + 2400 = 3600

Example 2:
Solution:
3853 + 6524 = 4000 + 7000 = 11,000

Example 3:
Solution:
8752 – 3654 = 9,000 – 4,000 = 5,000

Example 4:
Solution:
4538 – 2965 = 5,000 – 3,000 = 2,000

Example 5:
Solution:
1927 + 3185 = 2000 + 3,000 = 5,000

Example 6:
Solution:
3258 – 1698 = 3000 – 2000 = 1,000

Example 7:
Solution:
8735 + 6232 = 9000 + 6000 = 15,000

Example 8:
Solution:
1038 – 1028 = 1000 – 1000 = 0

Example 9:
Solution:
6352 + 5830 = 6,000 + 6,000 = 12,000

Example 10:
Solution:
9854 – 6385 = 10,000 – 6000 = 4,000

Question 2. Give a rough estimate (by rounding off to nearest hundreds) and also a closer estimate (by rounding off to nearest tens):
(a) 439 + 334 + 4,317
(b) 1,08,734 – 47,599
(c) 8,325 – 491
(d) 4,89,348 – 48,365
Make four such examples

Solution:
(a) 439 + 334 + 4,317
(i) Rough estimate (Rounding off to nearest hundreds)
439 + 334 + 4,317 = 400 + 300 + 4300 = 5,000
(ii) Closer estimate (Rounding off to nearest tens)
439 + 334 + 4317 = 440 + 330 + 4320 = 5090.

(b) 1,08,734 – 47,599
(i) Rough estimate (Rounding off to nearest hundreds)
1,08,734 – 47,599 = 1,08,700 – 47,600 = 61,100
(ii) Closer estimate (Rounding off to nearest tens)
1,08,734 – 47,599 = 1,08,730 – 47,600 = 61,130.

(c) 8325 – 491
(i) Rough estimate (Rounding off to nearest hundreds)
8325 – 491 = 8300 – 500 = 7800
(ii) Closer estimate (Rounding off to nearest tens)
8325 – 491 = 8330 – 490 = 7840.

(d) 4,89,348 – 48,365
(i) Rough estimate (Rounding off to nearest hundreds)
4,89,348 – 48,365 = 4,89,300 – 48,400 = 4,40,900
(ii) Closer estimate (Rounding off to nearest tens)
4,89,348 – 48,365 = 4,89,350 – 48,370 = 4,40,980

Example 1: 384 + 562

Solution:
(i) Rough estimate (Rounding off to nearest hundreds)
384 + 562 = 400 + 600
= 1,000
(ii) Closer estimate (Rounding off to nearest tens)
384 + 562 = 380 + 560
= 940

Example 2: 8765 – 3820

Solution:
(i) Rough estimate (Rounding off to nearest hundreds)
8765 – 3820 = 8800 – 3900
= 4900
(ii) Closer estimate (Rounding off to nearest tens)
8765 – 3820 = 8770 – 3820
= 4950

Example 3: 6653 – 8265

Solution:
(i) Rough estimate (Rounding off to nearest hundreds)
6653 + 8265 = 6700 + 8300
= 15,000
(ii) Closer estimate (Rounding off to nearest tens)
6653 + 8265 = 6650 + 8270
= 14920

Example 4: 3826 – 1262

Solution:
(i) Rough estimate (Rounding off to nearest hundreds)
3826 – 1262 = 3800 – 1300
= 2500
(ii) Closer estimate (Rounding off to nearest tens)
3826 – 1262 = 3830 – 1260
= 2570

Question 3. Estimate the following products using general rule:
(a) 578 x 161
(b)5281 x 3491
(c) 1291 x 592
(d) 9250 x 29
Make four more such examples.

Solution:

(a) 578 x 161 = 600 x 200 = 1,20,000
(b) 5281 x 3491 = 5000 x 3000 = 1,50,00,000
(c) 1291 x 592 = 1300 x 600 = 7,80,000
(d) 9250 x 29 = 9000 x 30 = 2,70,000

Example 1. 382 x 1062


Solution:
382 x 1062 = 400 x 1000 = 4,00,000

Example 2. 6821 x 1291
 
Solution:

6821 x 1291 = 7000 x 1000 = 70,00,000 

Example 3. 3858 x 9350
Solution:

3858 x 9350 = 4000 x 9000 = 3,60,00,000 

Example 4. 3405 x 7502
Solution:

3405 x 7502 = 3000 x 8000 = 2,40,00,000

 

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