NCERT Solutions Class 10th Maths Chapter – 1 Real Numbers
Textbook | NCERT |
Class | 10th |
Subject | Mathematics |
Chapter | 1st |
Chapter Name | Real Numbers |
Category | Class 10th Mathematics |
Medium | English |
Source | last doubt |
NCERT Solutions Class 10th Maths Chapter – 1 Real Numbers Exercise – 1.2 in This Chapter covers a range of topics including the Fundamental Theorem of Arithmetic, a review of Irrational Numbers, methods for finding the Least Common Multiple (LCM) and Highest Common Factor (HCF), Prime Factorization, and concepts related to Rational, Irrational, and Proving Irrational Numbers. This chapter provides comprehensive learning on these subjects.
NCERT Solutions Class 10th Maths Chapter – 1 Real Numbers
Chapter – 1
Real Numbers
Exercise – 1.2
1. Prove that √5 is irrational. Solution: Let us assume, that √5 is rational number. √5 = x/y (where, x and y are co-primes) Squaring both the sides, (y√5)2 = x2 Thus, x2 is divisible by 5, so x is also divisible by 5. Let us say, x = 5k, for some value of k and substituting the value of x in equation (1), we get, is divisible by 5 it means y is divisible by 5. Clearly, x and y are not co-primes. Thus, our assumption about √5 is rational is incorrect. Hence, √5 is an irrational number. |
2. Prove that 3 + 2√5 + is irrational. Solution: Let us assume 3 + 2√5 is rational. Then we can find co-prime x and y (y ≠ 0) such that 3 + 2√5 = x/y 2√5 = x/y – 3 √5 = 1/2(x/y – 3) Since, x and y are integers, thus, 1/2(x/y – 3) is a rational number. Therefore, √5 is also a rational number. But this contradicts the fact that √5 is irrational. So, we conclude that 3 + 2√5 is irrational. |
3. Prove that the following are irrationals: (i) 1/√2 Solution: 1/√2 Then we can find co-prime x and y (y ≠ 0) such that 1/√2 = x/y Since, x and y are integers, thus, √2 is a rational number, which contradicts the fact that √2 is irrational. Hence, we can conclude that 1/√2 is irrational. (ii) 7√5 Solution: 7√5 Then we can find co-prime a and b (b ≠ 0) such that 7√5 = x/y Since, x and y are integers, thus, √5 is a rational number, which contradicts the fact that √5 is irrational. Hence, we can conclude that 7√5 is irrational. (iii) 6 + √2 Solution: 6 +√2 Then we can find co-primes x and y (y ≠ 0) such that 6 +√2 = x/y⋅ √2 = (x/y) – 6 Since, x and y are integers, thus (x/y) – 6 is a rational number and therefore, √2 is rational. This contradicts the fact that √2 is an irrational number. Hence, we can conclude that 6 +√2 is irrational. |
NCERT Solutions Class 10th Maths All Chapter
- Chapter 1 – Real Numbers
- Chapter 2 – Polynomials
- Chapter 3 – Pair of Linear Equations in Two Variables
- Chapter 4 – Quadratic Equations
- Chapter 5 – Arithmetic Progressions
- Chapter 6 – Triangles
- Chapter 7 – Coordinate Geometry
- Chapter 8 – Introduction to Trigonometry
- Chapter 9 – Applications of Trigonometry
- Chapter 10 – Circles
- Chapter 11 – Areas Related to Circles
- chapter 12 – Surface Areas and Volumes
- Chapter 13 – Statistics
- Chapter 14 – Probability
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