NCERT Solutions Class 10th Maths Chapter – 1 Real Numbers Exercise – 1.2

NCERT Solutions Class 10th Maths Chapter – 1 Real Numbers

TextbookNCERT
Class 10th
SubjectMathematics
Chapter1st
Chapter NameReal Numbers
CategoryClass 10th Mathematics
MediumEnglish
Sourcelast doubt

NCERT Solutions Class 10th Maths Chapter – 1 Real Numbers Exercise – 1.2 in This Chapter covers a range of topics including the Fundamental Theorem of Arithmetic, a review of Irrational Numbers, methods for finding the Least Common Multiple (LCM) and Highest Common Factor (HCF), Prime Factorization, and concepts related to Rational, Irrational, and Proving Irrational Numbers. This chapter provides comprehensive learning on these subjects.

NCERT Solutions Class 10th Maths Chapter – 1 Real Numbers

Chapter – 1

Real Numbers

Exercise – 1.2

1. Prove that √5 is irrational.

Solution: Let us assume, that √5 is rational number.

√5 = x/y (where, x and y are co-primes)
y√5 = x

Squaring both the sides,

(y5)2 = x2
⇒ 5y2 = x2…………. (1)

Thus, x2 is divisible by 5, so x is also divisible by 5.

Let us say, x = 5k, for some value of k and substituting the value of x in equation (1), we get,
5y2 = (5k)2
⇒ y2 = 5k2

is divisible by 5 it means y is divisible by 5.

Clearly, x and y are not co-primes. Thus, our assumption about √5 is rational is incorrect.

Hence, √5 is an irrational number.

2. Prove that 3 + 2√5 + is irrational.

Solution: Let us assume 3 + 2√5 is rational.

Then we can find co-prime x and y (y ≠ 0) such that 3 + 2√5 = x/y
Rearranging, we get,

2√5 = x/y – 3

√5 = 1/2(x/y – 3)

Since, x and y are integers, thus,

1/2(x/y – 3) is a rational number.

Therefore, √5 is also a rational number. But this contradicts the fact that √5 is irrational.

So, we conclude that 3 + 2√5 is irrational.

3. Prove that the following are irrationals:

(i) 1/√2

Solution: 1/√2
Let us assume 1/√2 is rational.

Then we can find co-prime x and y (y ≠ 0) such that 1/√2 = x/y
Rearranging, we get,
√2 = y/x

Since, x and y are integers, thus, √2 is a rational number, which contradicts the fact that √2 is irrational.

Hence, we can conclude that 1/√2 is irrational.

(ii) 7√5

Solution: 7√5
Let us assume 7√5 is a rational number.

Then we can find co-prime a and b (b ≠ 0) such that 7√5 = x/y
Rearranging, we get,
√5 = x/7y

Since, x and y are integers, thus, √5 is a rational number, which contradicts the fact that √5 is irrational.

Hence, we can conclude that 7√5 is irrational.

(iii) 6 + √2

Solution: 6 +√2
Let us assume 6 +√2 is a rational number.

Then we can find co-primes x and y (y ≠ 0) such that 6 +√2 = x/y⋅
Rearranging, we get,

√2 = (x/y) – 6

Since, x and y are integers, thus (x/y) – 6 is a rational number and therefore, √2 is rational. This contradicts the fact that √2 is an irrational number.

Hence, we can conclude that 6 +√2 is irrational.

NCERT Solutions Class 10th Maths All Chapter

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