Find the smallest 4-digit number which is divisible by 18, 24 and 32.

NCERT Math Class 6th Question – 9 Exercise 3.7

Find the smallest 4-digit number which is divisible by 18, 24 and 32.

Solution:

The smallest 4-digit number = 1000.
To find the LCM of 18, 24 and 32, we have

∴ LCM = 2 x 2 x 2 x 2 x 2 x 3 x 3 = 288
Since, 288 is the smallest number which is exactly divisible by 18, 24 and 32.
But it is not a 4-digit number.

So, the multiple of 288 just above 1000 is: 1000 – 136 + 288 = 1152.
Hence, the required number is 1152.