Catherine threw a dice 40 times and noted the number appearing each time as shown below:| 1 | 3 | 5 | 6 | 6 | 3 | 5 | 4 | 1 | 6 | | 2 | 5 | 3 | 4 | 6 | 1 | 5 | 5 | 6 | 1 | | 1 | 2 | 2 | 3 | 5 | 2 | 4 | 5 | 5 | 6 | | 5 | 1 | 6 | 2 | 3 | 5 | 2 | 4 | 1 | 5 |
Make a table and enter the data using tally marks. Find the number that appeared.
(а) The minimum number of times
(b) The maximum number of times
(c) Find those numbers that appear an equal number of times. Solution We have the following table: | Number on the dice | Tally marks | Number of times | | 1 | |||| || | 7 | | 2 | |||| | | 6 | | 3 | |||| | 5 | | 4 | |||| | 4 | | 5 | |||| |||| | | 11 | | 6 | |||| || | 7 |
From the above table, we get
(a) The number 4 appeared 4 times which is the minimum.
(b) The number 5 appeared 11 times which is the maximum.
(c) The number 1 and 6 appear for the same number of times, i.e., 7. | 