NCERT Solutions Class 6th Maths Chapter – 11 Algebra Exercise – 11.2

Question 1. The side of an equilateral triangle is shown by l. Express the perimeter of the equilateral triangle using l.

Solution:
Side of equilateral triangle = l
Perimeter = l + l + l
= 3 l

Question 3. A cube is a three-dimensional figure as shown in (see figure). It has six faces and all of them are identical squares. The length of an edge of the cube is given by l. Find the formula for the total length of the edges of a cube.

Solution:
Length of an edge of the cube = l
Number of edges = 12
Total length of the edges = Number of edges × length of an edge
= 12 l

Question 4. The diameter of a circle is a line which joins two points on the circle and also passes through the centre of the circle. (In the adjoining figure (Fig 11.12) AB is a diameter of the circle; C is its centre). Express the diameter of the circle (d) in terms of its radius (r).

Solution:
Diameter = AB
= AC + CB
= r + r
= 2r
Hence, the diameter of the circle in terms of its radius is 2r.

Question 5. To find sum of three numbers 14, 27 and 13, we can have two ways;
(a) We may first add 14 and 27 to get 41 and then add 13 to it to get the total sum 54 or
(b) We may add 27 and 13 to get 13 to get 40 and then add 14 to get the sum 54.
Thus, (14 + 27) + 13 = 14 + (27 + 13)
This can be done for any three numbers. This property is known as the associativity of addition of numbers. Express this property which we have already studied in the chapter on whole numbers, in a general way, by using variables a, b, and c.

Solution:
For any three whole numbers a, b and c
(a + b) + c = a + (b + c)