Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case.

NCERT Math Class 6th Question – 8 Exercise 3.7

Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case.

Solution:

To find the LCM of 6, 15 and 18, we have

∴ LCM of 6, 15 and 18 = 2 x 3 x 3 x 5 = 90.
Here, 90 is the least number exactly divisible by 6, 15 and 18.
To get a remainder 5, the least number will be 90 + 5 = 95.
Hence, the required number is 95.

NCERT Math Class 6th Question – 1 Exercise 3.7Click here
NCERT Math Class 6th Question – 2 Exercise 3.7Click here
NCERT Math Class 6th Question – 3 Exercise 3.7Click here
NCERT Math Class 6th Question – 4 Exercise 3.7Click here
NCERT Math Class 6th Question – 5 Exercise 3.7Click here
NCERT Math Class 6th Question – 6 Exercise 3.7Click here
NCERT Math Class 6th Question – 7 Exercise 3.7Click here
NCERT Math Class 6th Question – 9 Exercise 3.7Click here
NCERT Math Class 6th Question – 10 Exercise 3.7Click here
NCERT Math Class 6th Question – 11 Exercise 3.7Click here

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